 CS_601 2nd Assignment Solution Spring 2019

## CS_601 2nd Assignment Solution Spring 2019

Question No. 1

After carefully analyzing the following figure that represents the encoding scheme based on the Differential Manchester approach, you are required to identify the bit pattern associated with the given encoding scheme:

Question No. 2

Suppose a telecommunication company’s booster is emitting a signal of 0.45W which is being passed through 12 devices. It has been observed that 8 of these devices are encountering noise of 3 microwatts whereas other 4 devices are encountering noise of 2 microwatts. Considering this information, you are required to calculate overall Signal to Noise Ratio (SNR) and SNRdB by writing all necessary formulas and calculation steps.

Solution:

Signal power=0.4w

Noise power of 8 device=8*0.000003

=0.000024w

Noise power of 4 devices=4*0.000002

=0.000008w

Total noise power=0.000003+0.000008

=0.000032

SNR=S/N

0.45/0.000032

=14062.5

SNRdb:

=10LOG10 SNRDB

=10LOG10  14602.5

=10 (4.148062535)

=41.4806

ANS = 41.9